SpletThe line y=kx+4 goes through the point (2,-2) Find the value k Expert Answer 1st step All steps Answer only Step 1/2 Given the equation of line is, View the full answer Step 2/2 Final answer Previous question Next question This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. SpletUsing the slope-intercept form of the equation in the video, y = -3/4x+8. We can substitute 8 for x, which gives us y = -3/4 (8)+8. The right hand side of the equation can be simplified by multiplying -3/4 * 8, then adding 8. This gives you 2. Therefore the equation now reads y = 2.
The lines 2y-kx+2=0 and y+x/2= 0 intersect at (1,-2). What is
Splet18. mar. 2024 · Given f(x)=3x^(2)+kx+19, and the remainder when f(x) is divided by x+3 is 37 , then what is the value of k ? 2 answers ... (-2,-4) and passes through the point (1,-4) 2 answers Find (g@f)(x) for the pair of functions and give the domain. f(x)=(12)/(x),g(x)=14-x. 2 answers ... the slope of the the line that goes throught (2,4) and (6,12) 2 answers Splet06. okt. 2024 · Find the value of k if it is known that the line y=kx+2 goes through point: P (−7, 12) Find the value of b if the graph the equation y=−3x+b goes through the given point A (−2, 4) B (5, 2) Advertisement Answer 20 people found it helpful BrainComp y = kx+2 , P (-7, 12) Calculation : 12 = k (-7) + 2 10 = k ( -7 ) k = -10/7 the howard center for wellness
Aside Y=kx+6 a tangent to x^2+y^2-10+8y=84. What is k?
SpletQuestion 1027625: For what values of k does the line y = kx –4 pass through the point of intersection of the lines y=2x–5 and y=–x+1? Found 2 solutions by mananth, robertb: Answer by mananth(16176) (Show Source): You can put this solution on YOUR website! SpletThe line y = kx +4, where k is a constant, is graphed in the xy-plane. If the line contains the... The SATMathGuy 4.39K subscribers Subscribe 1.4K views 1 year ago Test 3, Section 3... SpletTest if point of intersection is (1,-2) using equation y + x/2 = 0-2 + 1/2 not = 0 so point (1,-2) cannot be the point of intersection! I suspect point of intersection is ((1,-1/2) Using point … the howard company