If tana 5/12 then sin a + cos a .sec a
WebFor the first problem, use $\sec A = \frac{1}{\cos A}$, and $\csc A = \frac{1}{\sin A}$, then put them over a common denominator. Then convert $\tan$ and $\cot$ to $\sin$ and $\cos$ as you have done and put them over the same common denominator. Cancel these denominators and use $\sin^2 A + \cos^2 A = 1$ and you're done. Websec A - tan A = 5, or (1/cos A) - (sin A/cos A) = 5, or 1-sin A = 5 cos A, or 1-sin A = 5(1-sin^2 A)^0.5, or Square both sides (1-sin A)^2 = 25(1-sin^2 A) 1 - 2 sin A + sin^2 A = …
If tana 5/12 then sin a + cos a .sec a
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Web1 jun. 2024 · If tan A = 2, then evaluate sec A . sin A + tan^2A – cosec A. asked Jun 1, 2024 in Trigonometric Ratios of Acute Angles by HarshKumar ( 32.7k points) … WebSolve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more.
Web2 dec. 2015 · Explanation: Use the trig identity: tan2A = 2tanA 1 − tan2A (1). First, find tanA = sinA cosA. sinA = 3 5 --> sin2A = 9 25 --> cos2A = 1 − 9 25 = 15 25 - --> cosA = ± 4 5. Because A is in Quadrant II, its cos is negative. cosA = − 4 5 tanA = sinA cosA = (3 5)( − 5 4) = − 3 4 Replace value of tan A = -3/4 into identity (1) --> Web24 nov. 2014 · sinA = 3 5 = O H ⇒ Let {O = 3 H = 5. By Pythagorean Theorem, A = √H2 −O2 = √52 −32 = √16 = 4. Hence, secA = H A = 5 4. I hope that this was helpful. Answer link.
Web29 mrt. 2024 · Example 12 Express the ratios cos A, tan A and sec A in terms of sin A. cos A Since, cos2 A + sin2 A = 1 cos2 A = 1 – sin2 A cos A = ±√(1 −𝑠𝑖𝑛2 𝐴) Here, A is acute (i.e. … WebClick here👆to get an answer to your question ️ If tanA = 5/12 , find the value of sinA + cosA , where A is an acute angle. ... If 0 0 < A < 9 0 0 and sin A = 5 4 , then find the value of …
WebIf sin (a) +cos (a) =1/2, what is sin (a) * cos (a) equal to? Sin A + cos A = 1/2 Square on both sides. Sin^2 A + Cos^2 A + 2SinAcosA = 1/4 As (x+y)^2 = x^2+y^2+2xy. 1 + 2 sin A cos A = 1/4. As Sin^2 X + cos^2 X = 1. 2 sin A cos A = -3/4 Sin A Cos A = …
Web29 mrt. 2024 · Example 12Express the ratios cos A, tan A and sec A in terms of sin A.cos ASince, cos2 A + sin2 A = 1 cos2 A = 1 – sin2 A cos A = ±√(1 −𝑠𝑖𝑛2 𝐴)Here, A is acute ... Example 12 - Chapter 8 Class 10 Introduction to Trignometry (Term 1) Last updated at March 29, 2024 by Teachoo. filter abwasserrohrWebYou can put this solution on YOUR website! if tanA= 5/12, find sin(2a)-----If tan(A) = 5/12, y = 5 when x = 12--Then r = sqrt[5^2+12^2] = sqrt[169] = 13----So, sin(A) = y/r = 5/13 filter action in power automateWeb31 aug. 2013 · Consider, (sinA + cosA) × secA = (sinA + cosA)/cosA = (sinA/cosA + cosA/cosA) = tanA + 1 = (5/12) + 1 [Given tanA = 5/12] = 17/12 Recommend (1) … filter across sheets excelWeb12 feb. 2024 · (ii) (sin A + sec A) 2 + (cos A + cosec A) 2 = (1 + sec A cosec A) 2 (iii) t a n A − s i n A t a n A + s i n A = s e c A − 1 s e c A + 1 . cos = 20 1 27. If sin θ + cos θ = 2 sin (9 0 ∘ − θ), show that cot θ = 2 + 1. tan = c o t 1 28. If 7 sin 2 θ + 3 cos 2 θ = 4, 0 ∘ ≤ θ ≤ 9 0 ∘, then find the value of θ. PBP 29. If sec ... filter action menuWebsec A - tan A = 5, or (1/cos A) - (sin A/cos A) = 5, or 1-sin A = 5 cos A, or 1-sin A = 5 (1-sin^2 A)^0.5, or Square both sides (1-sin A)^2 = 25 (1-sin^2 A) 1 - 2 sin A + sin^2 A = 25 - 25 sin^2 A, or 26sin^2 A - 2 sin A - 24 = 0, or 13 sin^2 A - sin A - 12 = 0. sin A (1) = [+1+ (1+625)^0.5]/26 = [+1+25]/26 = 26/26 = 1 Hence A (1) = 90 deg growler station franchise informationWebIf tan A = 5/12, find the value of (sin A + cos A) sec A. ← Prev Question Next Question →. 0 votes. 105k views. asked Sep 7, 2024 in Mathematics by Mubarak (32.9k points) If tan … filter across rcWeb15 sep. 2024 · Example 1.7. Find the values of all six trigonometric functions of \(60^\circ \). Solution: Since we may use any right triangle which has \(60^\circ \) as one of the angles, we will use a simple one: take a triangle whose sides are all \(2 \) units long and divide it in half by drawing the bisector from one vertex to the opposite side, as in the figure on the right. growlers to go