WebApr 9, 2024 · Step-by-step explanation: As the expression given in the question. = (2 - 5i) (p + q)i. Simplify the above. = (2 - 5i) (pi + qi) = 2pi + 2qi - 5pi²- 5qi². As i² = -1. Put in the … WebAug 31, 2016 · How do you evaluate (2 − 5i)(p + q)i when p = 2 and q = 5i? Precalculus 1 Answer Shwetank Mauria Aug 31, 2016 (2 −5i)(p +q)i = 29i Explanation: While …
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WebHint: If p and q are both real, then one complex equation becomes two simultaneous real equations. Substitute one of the roots to obtain (1+2i)2 + (p+ 5i)(1+2i)+q(2−i) = 0 … WebWhen multiplying a number by its conjugate you should end up with a real number. You can check which 2 complex numbers, multiplied, give you a real number. Let's start with your school's answer. If you do (7-5i)* (-7+5i), you get 49 +70i-25i^2. This, in simplified form, is equal to 74+70i, which is a complex number, not a real number. kentucky derby dress shirts
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WebUse a Taylor polynomial of degree 2 at x=0 to approximate the desired value. Compare your answers with the results obtained by direct substitution. The profit (in thousands of … WebLet p=2+5i and q=3-4i. Calculate the following values and write them in a+bi form. a. p+q. b. p-q. c. p \cdot q p⋅q. ALGEBRA2 A group of students is asked to simplify the following … WebVideo transcript. Let z1 and z2 be two distinct complex numbers. And let z equal, and they say it's "1 minus t times z1 plus t times z2, for some real number with t being between 0 and 1." And they say, "If the argument w denotes the principal argument of a nonzero complex number w, then?" kentucky derby experience package